How do you match an aluminum-hull powerer with 0.55 KW on a ggregation gear? If you choose to match it with a R-series slash-barrel, then there are parameters that compare the demand for use with 19.71. And on a recently selectedreducing machine, one user asked to use 0.55 KW for aluminum-shell powerZip gear brakesTwisting is more than 70 nm. Then, according to the use parameters of the equipment, a suitable set of parameters will be selected for use on thereducing machine and on the electric equivalent model. This compares the use needs of households in the deceleration ratio with the output twist. Households may choose a paragraph for use in accordance with their own installation size requirements. That's some of the basic ideas of the type ofreducing machine. What would happen if you chose to use a k-seriesreducing machine to match the parameters that the gear-reducing performance would achieve? The deceleration ratio went closer to 20. 19, while the output rectangular was 77nm, so it would be possible to consider using thisreducing machine for matching use at this time, the corresponding type being the k37reducing machine. In the different types of matching, the interlocking of the gear-reducing machines can be used in multiple combinations. So how do you choose the appropriate electric andreducing models in this case? yesGeared motorThe selected top user requires aluminum-shell electric power, whether or not the aluminium-hull electric power is a cast iron electric power that does not change much between their output twists and their output rotations at the same level of power, so we follow the normalreducing machine model. The power of the electric machine is 40. 55 kw, with an output rectangular greater than 70 nm, with a reduction ratio of 19. 65, and the selected type of carpentry is a carpenter. at this point in time, we have three more direct parameters to select。

If the choice is..Induction motorWhat would happen to thereducing machine at this time? At this point in time, there is a close deceleration ratio of 19. 27. The output twister at this time is 73nm, and the corresponding type of the night gear brake is f37. So in these circumstances, can the output twister of thereducing machine meet the requirements? At this point, the correspondingreducing machine's output twist reached 75nm, and the correspondingreducing machine was r17. Taking into account the number ofreducing machines on _, only the s series in the back does not meet the requirements for use, while the three previously availablereducing machines can be selected because of thereducing ratio and the requirements for output twists. At this point, the output twister of the two slowdownrs corresponding to the rater does not meet the output twist required by the user, so the model of the series can be excluded. The power of a flat-rate reduction machine may be high, and the parameters of a reduction machine that is formed when it matches the power of a different generator are often large. And the type ofreducing machine that the user needs to match is the cone-wheel-reducing machine, whose output is more than 70 nms, chosen without any knowledge of thereducing gear-reducing machine, so how should we choose? What kind ofreducing ratio should we choose? It would be more appropriate for us to calculate the rate-down ratio from the formula. Parameters also apply to household use needs. if you chooseHelical-worm gearmotorwhat would be the parameters chosen at this time if they were matched? among the parameters, the reduction ratio of 19.65 relative to user usage requirements was 19.13 or 20.33. then let's see if some of the four series ofreducing machines are able to meet this requirement. http://boserlgearreducer.com/product/list-rxiliijiansuji-cn.html